Pv=nRT question

[akakakakak]

If anyone can explain this to me, I would appreciate it...

What is the new internal pressure off a given mass of nitrogen gas in a 400-ml vessel at 22(Celsius) and 1.2 atm, when heated to 60 (celsius) and compressed to 300 - ml?

I thought the answer would be

(1)(.400)(333)/(1.2)(.300)(295)

and the answer is stated as

(1.2)(.400)(333)/(1)(.300)(295)

I keep setting it up and can't get the the right answer

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[DATGod001]

This is easy and really know this!

PV/T=PV/T
(1.2)(.400)/(295)=P(.300)/(333)
(1.2)(.400)(333)/(295)(.300)= P

 

[DAT Destroyer]

If anyone can explain this to me, I would appreciate it...

What is the new internal pressure off a given mass of nitrogen gas in a 400-ml vessel at 22(Celsius) and 1.2 atm, when heated to 60 (celsius) and compressed to 300 - ml?

I thought the answer would be

(1)(.400)(333)/(1.2)(.300)(295)

and the answer is stated as

(1.2)(.400)(333)/(1)(.300)(295)

I keep setting it up and can't get the the right answer

You have the correct formula......but used it incorrectly. Read it carefully...They are asking for P2.....the initial pressure was 1.2 atm NOT 1atm . Try it again.....and let me know.

Dr. Romano

 

[akakakakak]

Easy peasy! Thank you for the help - genuinely appreciated!