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- Jun 30, 2005
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1. If x and y are integers such that x>y, which of the following cannot be a positive interger?
I. y(y-x)
II. y(x-y)
III. (x-y)/(y-x)
==> I picked x = 2, y = 1 to solve this problem.
1(1-2) = -1 so this cannot be +
1(2-1) = 1 so this can be +
(2-1)/(1-2) = 1/-1 = -1 so this cannot be +
However, there was no answer choice saying I and III are answers.
2. Over the course of a year, a certain factory increased its output by 90%. At the same time, it decreased its total working hrs by 20%. By what % did the factory increase its output per hr?
==> If I say it had 100% originally then increasing output by 90% changed it into 190%. If I say total working hour was 100 hrs, but it decreased by 20% then it means total working hour now is only 80 hrs.
100 hr = 190%
80 hr = ? %
152% is what I got for 80hr.
80hr = 80% was original
now it's 80hr = 152%
(152-80)/ 80 = 72/80 = 36/40 = 18/20 = 9/10 = 0.9 = 90% increase per hr than original.
But 90% is not the answer choice.
A. 70%
B. 110%
C. 112.5%
D. 137.5%
E. 237.5 %
please help me~ 🙂😍
I. y(y-x)
II. y(x-y)
III. (x-y)/(y-x)
==> I picked x = 2, y = 1 to solve this problem.
1(1-2) = -1 so this cannot be +
1(2-1) = 1 so this can be +
(2-1)/(1-2) = 1/-1 = -1 so this cannot be +
However, there was no answer choice saying I and III are answers.
2. Over the course of a year, a certain factory increased its output by 90%. At the same time, it decreased its total working hrs by 20%. By what % did the factory increase its output per hr?
==> If I say it had 100% originally then increasing output by 90% changed it into 190%. If I say total working hour was 100 hrs, but it decreased by 20% then it means total working hour now is only 80 hrs.
100 hr = 190%
80 hr = ? %
152% is what I got for 80hr.
80hr = 80% was original
now it's 80hr = 152%
(152-80)/ 80 = 72/80 = 36/40 = 18/20 = 9/10 = 0.9 = 90% increase per hr than original.
But 90% is not the answer choice.
A. 70%
B. 110%
C. 112.5%
D. 137.5%
E. 237.5 %
please help me~ 🙂😍
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