2 299678 Jan 31, 2010 #1 Members don't see this ad. How many ways can we give 3 prizes to two student, when both of them are equally eligible for all the prizes?
Members don't see this ad. How many ways can we give 3 prizes to two student, when both of them are equally eligible for all the prizes?
S Streetwolf Ultra Senior Member Verified Member 10+ Year Member Dentist 15+ Year Member Joined Oct 25, 2006 Messages 1,801 Reaction score 7 Jan 31, 2010 #2 kpark102 said: How many ways can we give 3 prizes to two student, when both of them are equally eligible for all the prizes? Click to expand... Do each of them only get 1 prize? If so this is a simple (3 P 2) problem. You are picking out the two prizes that the students will receive. Order matters. This equals 6 ways. Upvote 0 Downvote
kpark102 said: How many ways can we give 3 prizes to two student, when both of them are equally eligible for all the prizes? Click to expand... Do each of them only get 1 prize? If so this is a simple (3 P 2) problem. You are picking out the two prizes that the students will receive. Order matters. This equals 6 ways.
S Streetwolf Ultra Senior Member Verified Member 10+ Year Member Dentist 15+ Year Member Joined Oct 25, 2006 Messages 1,801 Reaction score 7 Feb 1, 2010 #4 kpark102 said: Yeah that's what I got, but the correct answer is 4 Click to expand... Maybe they wanted: (0, 3) (1, 2) (2, 1) (3, 0) Where (1,2) means student A got 1 prize and student B got 2 prizes. But that doesn't account for specific prizes in the (1,2) and (2,1) cases. If each student HAD to get a prize then only (1,2) and (2,1) are possible. In that case you have 3 choices for each though and it would STILL be 6 ways. Problem could be asking for something different. Or they have the wrong answer listed. Upvote 0 Downvote
kpark102 said: Yeah that's what I got, but the correct answer is 4 Click to expand... Maybe they wanted: (0, 3) (1, 2) (2, 1) (3, 0) Where (1,2) means student A got 1 prize and student B got 2 prizes. But that doesn't account for specific prizes in the (1,2) and (2,1) cases. If each student HAD to get a prize then only (1,2) and (2,1) are possible. In that case you have 3 choices for each though and it would STILL be 6 ways. Problem could be asking for something different. Or they have the wrong answer listed.
