Sin(2x)=2sin(x)cos(x)
Cos(2x)=cos^2(x)-sin^2(x)
Sin^2(x)+cos^2(x)=1
sin(-x)=-sin(x) because it's an odd function
cos(-x)=cos(x) because it's an even function
sin x= cos (90-x)
cos x= sin(90-x)
cos=1/sec
sin=1/csc
so yeah s&c to remember not c&c
S&C
tan=1/cot
Let's practice.
Simplify the following
sin(4x)/(2cos(2x)*csc(2x))
ok let's do this
sin(4x)=2sin(2x)*cos(2x)
csc(2x)=1/sin(2x)
cool let's get back to the equation at hand
2sin(2x)*cos(2x)/(2*cos(2x) *(1/sin(2x))
Get rid of cos(2x) they are the same
and flip 1/sin(2x) when it goes up it becomes sin(2x)
you get:
2 sin(2x) * sin (2x)/2
get rid of the 2
final result= sin^2(2x)
volia!
See it's not that hard, and this question is similar to a question on the destroyer, I changed some stuff in it.
If you are worried, just do some questions in ( qr destroyer )not math destroyer about them, because they are easier there, so you get familiar with them, don't worry about something and then you don't do anything about it!
If you worry do something to get rid of the fear.