Question regarding Titanic?

[fas376]

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If Jack weighed 70 kilograms and Rose weighed 50 kilograms, and the mass of the floating door was 10 kilograms, then could Jack have climbed on the door with Rose and saved himself or would the buoyant force not be strong enough?

 

[Melomare17]

answer: there is not enough information to answer this question since you don't have all necessary densities

 

[AOT11]

if jack weighed 70 kilograms and rose weighed 50 kilograms, and the mass of the floating door was 10 kilograms, then could jack have climbed on the door with rose and saved himself or would the buoyant force not be strong enough?

hahahahahahahahahahahahahaha best post ever


😀 😀 😀 😀 😀 😀

 

[HH8911]

If Jack weighed 70 kilograms and Rose weighed 50 kilograms, and the mass of the floating door was 10 kilograms, then could Jack have climbed on the door with Rose and saved himself or would the buoyant force not be strong enough?

Lmao

 

[misseskwee]

If only Jack were premed and was studying for the mcat.. maybe he coulda tried to figure it out, lol.

 

[joonage]

If only Jack were premed and was studying for the mcat.. maybe he coulda tried to figure it out, lol.

Or let go and end his misery ...

 

[misseskwee]

Or let go and end his misery ...

Puahahahaha 👍

 

[IncognitoGuy]

Or let go and end his misery ...

Might want to put a spoiler alert there..

 

[impact2d]

It's a trick question, weight is in newtons not kilograms lol

 

[Kennedypjp]

very good ,up you !!!

 

[brandonh4]

Answer: fk yes. She was just being a dramatic b*tch.

 

[ryanjacobs]

Hmm, trying to decide if this thread is more disturbing, or hilarious. I'll go with the latter.

 

[Jear]

It's a trick question, weight is in newtons not kilograms lol

I applaud your recognition of that fact, and simultaneously shake my head in disgust. Look what this exam reduces us to!

 

[nheit]

If Jack weighed 70 kilograms and Rose weighed 50 kilograms, and the mass of the floating door was 10 kilograms, then could Jack have climbed on the door with Rose and saved himself or would the buoyant force not be strong enough?

Somebody has to do it...

Let's assume that the door is about 7ft x 3ft x 2in. This would be approximately equivalent to 2.13m x 0.91m x 0.05m. V=2.13*0.91*0.025=0.1 m^3.

The density of water can be approximated to 1000 kg/m^3 although it would be slightly less given that the temperature of the water was around 0C.

We have to look up the density of different types of wood used on the Titanic.
Oak: 0.6-0.9 (* 10^3 kg/m^3)
Teak:0.6-0.9 (* 10^3 kg/m^3)
Maple 0.6-0.75 (* 10^3 kg/m^3)

We'll give Rose the benefit of the doubt and say that the density of the wood is at its minimum possible value (assuming that the door was solid) at 600 kg/m^3.

With this info we get the mass of the door to be more like 28kg (61 lbs) which seems more plausible than 10kg, but if you go through the calculations with 10kg, you can see that this difference doesn't really matter.

We then ask, "At what additional weight would the door no longer stay afloat?" This would be when the buoyant force equals the force of gravity on the door and whatever weight is on it. Instead of doing all those calculations, we can make a simple equality: (the mass of the door + maximum additional mass)/(volume of the door) = density of water. (28+M)/0.1=1000. M = 72 kg. This would be enough to hold up either Jack (70 kg) or Rose (50 kg) alone but not both (120 kg). Thus, all Jack can do is hold on to the edge with the majority of his body submerged. Body heat is lost 25 times faster in cold water than in cold air as poor Jack found out.

http://www.youtube.com/watch?v=pXvlKYcdSc0#t=0m51s

 

[Lazybum2014]

Somebody has to do it...

Let's assume that the door is about 7ft x 3ft x 2in. This would be approximately equivalent to 2.13m x 0.91m x 0.05m. V=2.13*0.91*0.025=0.1 m^3.

The density of water can be approximated to 1000 kg/m^3 although it would be slightly less given that the temperature of the water was around 0C.

We have to look up the density of different types of wood used on the Titanic.
Oak: 0.6-0.9 (* 10^3 kg/m^3)
Teak:0.6-0.9 (* 10^3 kg/m^3)
Maple 0.6-0.75 (* 10^3 kg/m^3)

We'll give Rose the benefit of the doubt and say that the density of the wood is at its minimum possible value (assuming that the door was solid) at 600 kg/m^3.

With this info we get the mass of the door to be more like 28kg (61 lbs) which seems more plausible than 10kg, but if you go through the calculations with 10kg, you can see that this difference doesn't really matter.

We then ask, "At what additional weight would the door no longer stay afloat?" This would be when the buoyant force equals the force of gravity on the door and whatever weight is on it. Instead of doing all those calculations, we can make a simple equality: (the mass of the door + maximum additional mass)/(volume of the door) = density of water. (28+M)/0.1=1000. M = 72 kg. This would be enough to hold up either Jack (70 kg) or Rose (50 kg) alone but not both (120 kg). Thus, all Jack can do is hold on to the edge with the majority of his body submerged. Body heat is lost 25 times faster in cold water than in cold air as poor Jack found out.

http://www.youtube.com/watch?v=pXvlKYcdSc0#t=0m51s

Wait I think I love you for this.