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Questions thread

Discussion in 'MCAT Discussions' started by Cerberus, Mar 27, 2004.

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  1. Cerberus

    Cerberus Heroic Necromancer
    Physician 10+ Year Member

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    I have some more questions so i thought I'd start a thread where people can ask questions and get help:)

    My q:

    I want to get this straight, when a capicator is charging, the current initially increases and then decreases until it reaches zero (the capacitor becomes fully charged) but the voltage remains the same the entire time?
     
    #1 Cerberus, Mar 27, 2004
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  2. sdnstud

    sdnstud 1K Member
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    you've confused V for battery with V for capacitor.

    As the capacitor charges, V for battery stays the same. (the definition of a bettery is constant V for a long ass time)

    For the capacitor, as it charges, V will increase proportionally with Q. Remember Q=CV. C remains constant because C=eA/d.
     
    #2 sdnstud, Mar 27, 2004
  3. Cerberus

    Cerberus Heroic Necromancer
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    Ok, but the V for capacitor doesnt come into play till the capacitor is discharged - in which case it would drop exponetially - right?
     
    #3 Cerberus, Mar 27, 2004
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