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Questions thread

Discussion in 'MCAT: Medical College Admissions Test' started by Cerberus, Mar 27, 2004.

  1. Cerberus

    Cerberus Heroic Necromancer
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    I have some more questions so i thought I'd start a thread where people can ask questions and get help:)

    My q:

    I want to get this straight, when a capicator is charging, the current initially increases and then decreases until it reaches zero (the capacitor becomes fully charged) but the voltage remains the same the entire time?
     
  2. sdnstud

    sdnstud 1K Member
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    you've confused V for battery with V for capacitor.

    As the capacitor charges, V for battery stays the same. (the definition of a bettery is constant V for a long ass time)

    For the capacitor, as it charges, V will increase proportionally with Q. Remember Q=CV. C remains constant because C=eA/d.
     
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  3. Cerberus

    Cerberus Heroic Necromancer
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    Ok, but the V for capacitor doesnt come into play till the capacitor is discharged - in which case it would drop exponetially - right?
     

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