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Questions thread

Cerberus

Heroic Necromancer
15+ Year Member
Dec 13, 2001
15,128
185
316
  1. Attending Physician
I have some more questions so i thought I'd start a thread where people can ask questions and get help:)

My q:

I want to get this straight, when a capicator is charging, the current initially increases and then decreases until it reaches zero (the capacitor becomes fully charged) but the voltage remains the same the entire time?
 

sdnstud

1K Member
10+ Year Member
15+ Year Member
Jul 29, 2003
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you've confused V for battery with V for capacitor.

As the capacitor charges, V for battery stays the same. (the definition of a bettery is constant V for a long ass time)

For the capacitor, as it charges, V will increase proportionally with Q. Remember Q=CV. C remains constant because C=eA/d.
 

Cerberus

Heroic Necromancer
15+ Year Member
Dec 13, 2001
15,128
185
316
  1. Attending Physician
Originally posted by sdnstud
you've confused V for battery with V for capacitor.

As the capacitor charges, V for battery stays the same. (the definition of a bettery is constant V for a long ass time)

For the capacitor, as it charges, V will increase proportionally with Q. Remember Q=CV. C remains constant because C=eA/d.

Ok, but the V for capacitor doesnt come into play till the capacitor is discharged - in which case it would drop exponetially - right?
 
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