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[Columbia22]

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How do you reduce imines (H+/H20, NaBH4, LialH4, etc)?? Also, did anyone have that "litter" stand alone question?? (ie, 1.4, 3.4, 1, 0)

 

[indo]

I picked the acid on that one. I figured the other two would f* with the carbonyl group.

 

[Columbia22]

I chose H+ also, but i think its NaBH4

 

[indo]

Was it an ester that was to be reduced?
If it was the LiAlH is the right answer....shi+

 

[Jason110]

I picked 0 for the litter question... and here is my reasoning why the probability of two males and two female in a litter is zero:

a zygote is formed by the union of two gametes (sperm and egg)... So i figured this was an 'identical twin' question in disguise. Maybe? Maybe?

Eh. Whatever. At least the test is done.

-Jason

 

[indo]

Originally posted by Jason110
I picked 0 for the litter question... and here is my reasoning why the probability of two males and two female in a litter is zero:

a zygote is formed by the union of two gametes (sperm and egg)... So i figured this was an 'identical twin' question in disguise. Maybe? Maybe?

Eh. Whatever. At least the test is done.

-Jason

I agree. They're going to be identical quadruplets with matching chroms. so they're all going to be male or all going to be female.

Speaking of female, if I had any money I'd go to a strip club.

 

[StanSteel]

About the imine stuff
I put H+/H20

I looked it up in two textbooks already and reduction of imines is in neither of them.!!!

Talk about stuff that they expect you to answer right on the test.

 

[Columbia22]

its most probably NaBH4, damn bastards

 

[blz]

It was NaBH4 for that one.

The litter one was 0, correctly shown by Jason's reasoning.

 

[sgilani]

I put NaBH4. LiALH4 is a stronger reducing agent and usually used for esters. I didn't even consider the H+ which makes me think now...

 

[peterockduke]

http://www.rhodium.ws/chemistry/redamin.zirconium.html

"Novel reducing agent prepared from zirconium tetrachloride and sodium borohydride reduces various functional groups including C=0 double bonds, C=N double bonds and C-N triple bonds in excellent yield (85-96%) under mild condition."

Hold the applause.




LiAlH4 is nasty and will f^ck up everything - I know this already.

It's definitely NaBH4 ...

strong acid cleaves an ester to a carboxyl anyway so it can't be H+/H20

don't worry.... some of us didn't take 9million baby bio classes so we got smoked on the physiology questions

good thing I DID take anatomy...
oh yeah, my test was at least 45% orgo (muahahhahahhaha)

 

[Winston Smith]

I put NaBH4 as well

for the litter one, I put 1. Why is it 0? I'm sorry but I'm tired -- I just don't see the reasoning there

 

[gibna]

Because the offspring are all identical twins, so they are all either female or male.

 

[StanSteel]

For the litter its 0 because the zygote is dividing twice, to make 4 cells, that make the four babies.
...
Zygote divides
Zygote divides

What sex was the zygote?
Yes it only had one sex!!!!!

Therefore if it divides twice by mitosis, it's not gonna go transsexual in the process. Get it ?? 🙂

 

[Winston Smith]

this would probably make more sense if I remembered the info they gave...what was that again?

i remember doing that problem in like 5 secs i thought it was a really easy question.

 

[gibna]

how about the interstitual fluid question. Is water the most abundant thing there?

 

[Chronotropic]

Originally posted by gibna
how about the interstitual fluid question. Is water the most abundant thing there?

I didn't have that question, but I'm pretty sure that water would be the answer.

 

[sibot2]

Originally posted by indo
Was it an ester that was to be reduced?
If it was the LiAlH is the right answer....shi+

Indo, I agree with you. I thought it was reduction of an ester too, not an amine. I beleive it was Passage 2 from BS, something about chemical is needed to go from Compound 6 to Compound 7 or the very last step in the synthesis.

Can anyone confirm? My mind is still reeling.

 

[Columbia22]

it was actually a reduction of an IMINE, without reducing an ester