For me personally, I like to use the "OIL RIG" instead of "LEO GER", I just remember it better...I understand the concept, but I can't seem to figure out the half reactions. Can someone please explain this to me?
Thank you in advance.
Remember Cations will go to the Cathode. Cathode = Reduction = Gain of e- (this will go on the left side of the equation)Thank you both. I guess my problems is recognizing which one is losing electron and which one is gaining. I just can't get a hang of it.
Can you please explain your technique?
For example, is my assumption correct here?
2Al + 3H2SO4 --> Al2(SO4)3 + 3H2
is this right?
Al --> Al3+ + 3e-
SO4 + 2e- --> SO4-2
Your right but I wouldn't even bring Cathode/Anode in for this type of question. Just know OIL RIGRemember Cations will go to the Cathode. Cathode = Reduction = Gain of e- (this will go on the left side of the equation)
Al+3 + 3e- ---> Al
Then you have Anions which will go to the Anode. Anode = Oxidation = Loss of e- (this will go on the right side of the equation)
SO4 ----> SO4-2 + 2e-
Somebody please make sure I did this right, I dont want someone to memorize the wrong information lol.