Reducing agents= oxidation=loss of electrons, so metals can easily lose electrons because they are not very electronegative while nonmetals are good oxidizing agents and are very electronegative so will accept electrons readily.
therefore Li is an excellent reducing agent will F is an excellent oxidizing agent
Reducing agents= oxidation=loss of electrons, so metals can easily lose electrons because they are not very electronegative while nonmetals are good oxidizing agents and are very electronegative so will accept electrons readily.
therefore Li is an excellent reducing agent will F is an excellent oxidizing agent
Thats an interesting question... from Orgo I remember that LiAlH4 and NaBH4 each are excellent reducing agents and both are metals so that means Saber Tooth has a good point!
Thats an interesting question... from Orgo I remember that LiAlH4 and NaBH4 each are excellent reducing agents and both are metals so that means Saber Tooth has a good point!
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