Relative Speed of a Gas at a Different Temp

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v = sqrt(3RT/m)

v'/v = sqrt(3RT'/m)/sqrt(3RT/m)

=sqrt(T')/sqrt(T)

=sqrt(T'/T)

I guess I don't see why you inverted the relationship.

It makes sense that velocity goes up as temperature goes up and in the formula you posted, if T1 > T2, it will say that the temperature goes down.

So I would think you need to flip the temps to be v'/v =sqrt(T'/T)
 
I think you got that equation mixed up with the one for mass: V1/V2 = sqrt (M2/M1).

Mass and velocity are inversely proportional. Temperature and velocity are directly proportional.
 
Yes, and it can all be derived from the formula without memorizing each separate case.
 
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