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what's left of it, anyway
@OP: You can do the math.

Agreed. Just thought it was a little harsh, that's all.Maybe if his followup question had anything to do with the concepts 😉
solubility1 = (10^-6)^(1/2)
solubility2 = [(10^-6)/(27)]^(1/4)
Which is more soluble?
OP, since solubility is a measure of the number of particles in solution, the greater x value between the two will be more soluble. Comparing the two;
A1B1 has a solubility or x-value = (10^-6)^(1/2) = 10^-3
A1B3 has a solubility or x-value = (10^-6)/(27)]^(1/4) = 10^-2
Thus A1B3 is more soluble.
can you just answer my question?
thanks
Remember that the solubility constant (Ksp) is a measurement of how well a substance dissolves in a specific amount of solvent. Since these two molecules have the same Ksp, yet one has more dissolvable components (A1B3), it must be more soluble.
Ashley, first off, ignore the losers who waste their time and your time by posting ridicule. The psychological basis behind their actions is to combat insecurity by trying to convince themselves that they're intelligent. Similar to the reason why they play world of war craft all day to give themselves a sense of accomplishment, as it is absent in their real life.
Moving on... Remember that the solubility constant (Ksp) is a measurement of how well a substance dissolves in a specific amount of solvent. Since these two molecules have the same Ksp, yet one has more dissolvable components (A1B3), it must be more soluble. No need to do risky calculations as they waste your time on the test and can lead you down the wrong path.
All the best.
🤣Do you have to make fun because you're a miserable reapplicant stuck in an SMP? Are you that insecure? pfff... 🤣