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The question asks for the max # of moles of NiCO3 in a precipitation reaction. There is 6.57 g pf NiSO4*6 H2O (MM=262.84) and 7.15g Na2CO3*10 H2O(MM=286.16) dissolved in water. The answer is 0.025 mol which I got. I just want to clarify my reasoning.
I calculated only the # of moles for Ni solution{.025 mol( which is the same for sodium carbonate)] but the AAMC explanation calculated MM for both. Why is that? Is it because we have to take into account that Nickel sulfate is soluble and sodium carbonate is slightly soluble
Thanks!
I calculated only the # of moles for Ni solution{.025 mol( which is the same for sodium carbonate)] but the AAMC explanation calculated MM for both. Why is that? Is it because we have to take into account that Nickel sulfate is soluble and sodium carbonate is slightly soluble
Thanks!