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Stats Question, need HELP please!!!

Discussion in 'DAT Discussions' started by iJackTeeth, Dec 4, 2008.

  1. iJackTeeth

    2+ Year Member

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    John was interviewed at 4 schools, the interview to acceptance percentage at the four schools were 45%, 35%, 70%, and 56%, what is johns chance of getting at least one acceptance to a school?
     
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  3. Streetwolf

    Streetwolf Ultra Senior Member
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    Say the chance was 80% (it probably isn't). That means the chance he was accepted to NONE of the schools is 20%. So we want to solve for the chances he wasn't accepted anywhere and then figure out the chances he got at least 1 acceptance.

    P(no acceptance) = 55% * 65% * 30% * 44% (these are the percentages obtained when you do (100 - x) to all four percentages above - they represent the percentage of not getting accepted after an interview)

    P(no acceptance) = (0.55)(0.65)(0.30)(0.44) = 0.04719
    P(no acceptance) = 4.719%
    P(acceptance somewhere) = 100 - 4.719 = 95.381%
     
  4. Sublimation

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    Wats the answer? is it 51.5 percent ????
     
  5. Sublimation

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    oooohhhh,:idea: now that makes more sense. thanks.
     
  6. IWantSmile

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    It makes so much sense when you explain in this. :rolleyes:
     

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