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Hi I was wondering if anybody could please help me with this question.
The Berkeley Review Titration Table Passage Question 11:
Given: 25 ml of a 0.1 M sample of the acid is used. Titrant is a strong base 0.05M and it takes 50 ml to reach the equivalence point.
It takes 14 ml of base (titrant) to make the PH of the solution 7.
Question: when the PH is 7.00, what is true about the ratio of weak acid to conjugate base in solution?
Anwer: The weak acid exceeds the conjugate base in the ratio of 2.53:1.
TBR's answer explanation says that the ratio of acid to base is 36:14 or about 2.53:1... Where did the 36 come from? I get that it's from 50-14 but why isn't it 25ml? There's only 25 ml of acid in the solution.... And why are we supposed to use the ratios of the volumes?
Also, another way to finding the answer is to use the henderson-hasselbach equation but I don't see how they did this.
Any help would be appreciated. Thank you!
The Berkeley Review Titration Table Passage Question 11:
Given: 25 ml of a 0.1 M sample of the acid is used. Titrant is a strong base 0.05M and it takes 50 ml to reach the equivalence point.
It takes 14 ml of base (titrant) to make the PH of the solution 7.
Question: when the PH is 7.00, what is true about the ratio of weak acid to conjugate base in solution?
Anwer: The weak acid exceeds the conjugate base in the ratio of 2.53:1.
TBR's answer explanation says that the ratio of acid to base is 36:14 or about 2.53:1... Where did the 36 come from? I get that it's from 50-14 but why isn't it 25ml? There's only 25 ml of acid in the solution.... And why are we supposed to use the ratios of the volumes?
Also, another way to finding the answer is to use the henderson-hasselbach equation but I don't see how they did this.
Any help would be appreciated. Thank you!