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Okay I'm not sure if I'm tweaking out but I think the answer to this question is wrong. Can someone double check?
One mol of helium is equilibrated at STP in a cylinder equipped with a moveable piston of negligible mass. After equilibration the piston is insulated, and a transformation is completed resulting in the temperature of the gas falling to 100˚C, with atmospheric pressure continually maintained. What is the final volume of the gas? Recall that the internal energy of a monatomic ideal gas is given as: E = (3/2)RT. (R = 0.08 L.atm/mol.K)
Correct Answer: 10.1 L
Explanation
One mol of helium is equilibrated at STP in a cylinder equipped with a moveable piston of negligible mass. After equilibration the piston is insulated, and a transformation is completed resulting in the temperature of the gas falling to 100˚C, with atmospheric pressure continually maintained. The final volume of the gas is 10.1 L.
Since the question tells us the piston is insulated (q = 0), we know all changes in E are because of pressure-volume work. So ΔE = PΔV = 3/2 RΔT.
3/2 R(ΔT) = 3/2(0.08)(100) = (3/2)(8) = 12
12 = PΔV = 1 atm (ΔV)
ΔV = 12 L
And since 1 mol of an ideal gas at STP has 22.4 L of volume, the resultant volume is ~10.4 L, making 10.1 L the best answer.
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I put 22.4 and I believe that's correct. Why are they using (C) in the equation for temp? It should be 173 because the constant is in (K)
One mol of helium is equilibrated at STP in a cylinder equipped with a moveable piston of negligible mass. After equilibration the piston is insulated, and a transformation is completed resulting in the temperature of the gas falling to 100˚C, with atmospheric pressure continually maintained. What is the final volume of the gas? Recall that the internal energy of a monatomic ideal gas is given as: E = (3/2)RT. (R = 0.08 L.atm/mol.K)
Correct Answer: 10.1 L
Explanation
One mol of helium is equilibrated at STP in a cylinder equipped with a moveable piston of negligible mass. After equilibration the piston is insulated, and a transformation is completed resulting in the temperature of the gas falling to 100˚C, with atmospheric pressure continually maintained. The final volume of the gas is 10.1 L.
Since the question tells us the piston is insulated (q = 0), we know all changes in E are because of pressure-volume work. So ΔE = PΔV = 3/2 RΔT.
3/2 R(ΔT) = 3/2(0.08)(100) = (3/2)(8) = 12
12 = PΔV = 1 atm (ΔV)
ΔV = 12 L
And since 1 mol of an ideal gas at STP has 22.4 L of volume, the resultant volume is ~10.4 L, making 10.1 L the best answer.
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I put 22.4 and I believe that's correct. Why are they using (C) in the equation for temp? It should be 173 because the constant is in (K)
