S SonhosDaVida Full Member 7+ Year Member Aug 2, 2018 #1 Advertisement - Members don't see this ad Hey guys, this is from TBR. Why is 50 mL used as the volume of strong base required to reach the equivalence point of the titration of a weak acid?
Advertisement - Members don't see this ad Hey guys, this is from TBR. Why is 50 mL used as the volume of strong base required to reach the equivalence point of the titration of a weak acid?
P PlsLetMeIn21 Full Member 5+ Year Member Aug 11, 2018 #3 In the paragraph above the table, they tell you that you have 50mL of 0.10M weak acid and you are adding 0.10M KOH(aq). Using M1V1 = M2V2, you get (0.1)(50) = (0.1)(Vbase). You need 50 mL of base to neutralize the weak acid. Upvote 0 Downvote
In the paragraph above the table, they tell you that you have 50mL of 0.10M weak acid and you are adding 0.10M KOH(aq). Using M1V1 = M2V2, you get (0.1)(50) = (0.1)(Vbase). You need 50 mL of base to neutralize the weak acid.
