Titration curve question

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SonhosDaVida

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Hey guys, this is from TBR. Why is 50 mL used as the volume of strong base required to reach the equivalence point of the titration of a weak acid?
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In the paragraph above the table, they tell you that you have 50mL of 0.10M weak acid and you are adding 0.10M KOH(aq). Using M1V1 = M2V2, you get (0.1)(50) = (0.1)(Vbase). You need 50 mL of base to neutralize the weak acid.
 
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