Titration question

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lex1489

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"A solution of NaOH and HF are titrated to the endpoint of a titration. The final solution will contain?"

Answer: H2O, H+, OH-, HF, Na+ and F-

Why doesn't all the HF dissociate in basic solution? Shouldn't all that OH- take the H's off of HF?
 
Everything's an equilibrium. Bit of a tricky question. If you drop sodium fluoride in water, some of that fluoride is going to abstract a proton from water, forming OH-.
 
"A solution of NaOH and HF are titrated to the endpoint of a titration. The final solution will contain?"

Answer: H2O, H+, OH-, HF, Na+ and F-

Why doesn't all the HF dissociate in basic solution? Shouldn't all that OH- take the H's off of HF?

F- is a decent base. It'll take a hydrogen off of a water molecule.
 
Would this be the case for any weak acid (or weak base for that matter)-- that regardless of how much strong base (or strong acid for the weak base) is added, some acid (base) will always remain? That it will never dissociate completely?
 
Would this be the case for any weak acid (or weak base for that matter)-- that regardless of how much strong base (or strong acid for the weak base) is added, some acid (base) will always remain? That it will never dissociate completely?

yep...weak acids/bases don't dissociate completely.
 
what do you mean all salts can dissociate completely?

assuming solution is not saturated (or supersaturated), most salts are 100% soluble in water, so it breaks down into its respective cations and anions.

obviously there's some insoluble salts though, like AgCl and BaSO4
 
I think it's quite a stretch to say most salts are 100% soluble in water, especially since 100% soluble doesn't have much meaning, but yeah.
 
Yeah.. considering the fact that HF is a weak acid.. its conjugate must be not strong but somewhat decent... so it will definitely attract proton from the water...
 
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