A runner hopes to complete the 10,000 m run in less than 30 min. After exactly 27 min there are still 1100 m to go. The runner must then acceleratie at .2m/s2 for how many seconds in order to achieve the desired time?

Aka

Vo= ((10,000m-1100m)/(27minuts * 60 seconds))(We assume it is constant velocity) = 5.49 m/s

A= .2 m/s^2

The magic equation you are looking for is

D= Vo*t+(1/2)*a*t^2

D=(1100)

So

1100=5.49*t+(1/2)*(.2)*t^2

right?

Solve for t and that is your answer