If you look at the information they gave you, the numerical value of Ksp, all of them are insoluble. Thus, to find out the highest electrical conductance is to find out which compound give you the largest the solubility product constant.
If you look at the information they gave you, the numerical value of Ksp, all of them are insoluble. Thus, to find out the highest electrical conductance is to find out which compound give you the largest the solubility product constant.
If you look in the Kaplan notes listing solubility rules, only CuBr is considered soluble, the rest insoluble. Considering this, the ksp values don't make sense at all.
find X for each
you can eliminate AgI very quickly( X^2= 8.5 X 10^-17===> X~ 9. 10^-9)
X^2 for CaSO4 ======> X^2= 2.4 X 10-5 ====> X~ 5. 10^-3 it is bigger than others.
the answer will be A ( ~ 0.005)
If you look in the Kaplan notes listing solubility rules, only CuBr is considered soluble, the rest insoluble. Considering this, the ksp values don't make sense at all.
Why would you be concerned with the "solubility rules" when the absolute solubilities are given in the form of Ksp? Since calcium sulfate has the highest solubility of the 4 compounds listed, one would expect it to generate the most ions and thus have the highest electrical conductance.
Why would you be concerned with the "solubility rules" when the absolute solubilities are given in the form of Ksp? Since calcium sulfate has the highest solubility of the 4 compounds listed, one would expect it to generate the most ions and thus have the highest electrical conductance.
Because the solubility rules in an aqueous solution state that all choices are insoluble except CuBr, so it would be expected that CuBr would have greatest Ksp. The fact that it doesn't causes the confusion, even more so when you have an additional problem like this:
ok so the best electrical conductor will be the one that ionizes the most in aqueous solution. They will all form 2 ions when they break, so no multiplication is necessary (Something like K2SO4 you would multiply the Ksp by 3 since it makes three ions). The biggest Ksp will dissociate the most. Therefore A is correct. There is a problem similar in destroyer, with a higher level of difficulty because it takes into account more that 2 ions like i said above. if you want me to find the problem number let me know.
Because the solubility rules in an aqueous solution state that all choices are insoluble except CuBr, so it would be expected that CuBr would have greatest Ksp. The fact that it doesn't causes the confusion, even more so when you have an additional problem like this: