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A 1 kg meter stick is attached to the ceiling by a string at the 40 cm mark. If a 3 kg mass is attached to the meter stick at the end labeled 0 cm,what mass placed at the 70 cm mark would balance the meter stick?
Ans: 3.67 Kg
Okay so 1 meter = 100 cm,
Torque Clock Wise = Torque Counter CW
Pivot point is the center of mass, so at the 50 cm line.
Torque = Distance to pivot point x F
Gs Cancel out and I get...
1kg x (10 cm) + 3kg x (50cm) = X kg * (20 cm)
The ans i get is 8 kg??
Ans: 3.67 Kg
Okay so 1 meter = 100 cm,
Torque Clock Wise = Torque Counter CW
Pivot point is the center of mass, so at the 50 cm line.
Torque = Distance to pivot point x F
Gs Cancel out and I get...
1kg x (10 cm) + 3kg x (50cm) = X kg * (20 cm)
The ans i get is 8 kg??