- Joined
- Mar 7, 2008
- Messages
- 396
- Reaction score
- 0
Guys what does this mean:
KOH(s) ----> KOH (aq) + 43KJ
does this mean this is an exothermic reaction or endothermic.
i thought if the energy is negative, then it is exothermic. and when it is + then it is endo.
so here it means that the energy is given off or energy is put in also what does it mean when we have this:
+ 43KJ KOH(s) ----> KOH (aq)
this means that energy is put in, right?
then for a problem like this:
22. The addition of 14g solid KOH pellets to water cause the following to take place;
KOH(s) ----> KOH (aq) + 43KJ
what is the enthalpy change for the dissolution of the 14g of KOH?
ans is -10.2KJ but why?
now we have to do the following:
14gKOH (1mole KOH/56g KOH) = 1/4 mole
then 1/4 (43KJ) or 1/4(-43KJ)
i don't get this part!
would someone explain. thanks.
KOH(s) ----> KOH (aq) + 43KJ
does this mean this is an exothermic reaction or endothermic.
i thought if the energy is negative, then it is exothermic. and when it is + then it is endo.
so here it means that the energy is given off or energy is put in also what does it mean when we have this:
+ 43KJ KOH(s) ----> KOH (aq)
this means that energy is put in, right?
then for a problem like this:
22. The addition of 14g solid KOH pellets to water cause the following to take place;
KOH(s) ----> KOH (aq) + 43KJ
what is the enthalpy change for the dissolution of the 14g of KOH?
ans is -10.2KJ but why?
now we have to do the following:
14gKOH (1mole KOH/56g KOH) = 1/4 mole
then 1/4 (43KJ) or 1/4(-43KJ)
i don't get this part!
would someone explain. thanks.