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What is ring strain?
Started by BrokenGlass
Is that when you know your girlfriend will dump you if she doesn't get an engagement ring soon?
Lol, all too familiar with that. The ring strain that occurs when atoms are confined to ring systems, and therefore subject to the strain of distorting their ideal bond angles, is much easier to deal with.
a smaller diamond has higher ring strain per mole but not quite as high as cubic zirconium
that shiz is more reactive than HI
Lol, all too familiar with that. The ring strain that occurs when atoms are confined to ring systems, and therefore subject to the strain of distorting their ideal bond angles, is much easier to deal with.
I don't know. According to EK, stress is what we do to an object. Strain is how the object responds. Modulus of elasticity (a constant within some range) is what connects the concepts of stress and strain.
Ring strain refers to the lack of stability of a molecule that occurs because of unfavorable high-energy "spatial" arrangement orientations of its atoms. (High energy = bad. The lower the energy of a molecule, the more stable the molecule).
There are two types of ring strain:
(1) torsional strain:
think about t-butyl groups on every carbon of a cyclohexane--very crowded right? that's torsional strain--all the hydrogens around each other. the hydrogens want to be furthest away from each other. that's why for cyclohexanes, the bulkiest groups are favored in the equatorial position..but this is going far more in depth than is needed)
(2) angle strain: http://research.cm.utexas.edu/nbauld/teach/cycloprop.html
That site talks about it in more detail.
I hope this was somewhat helpful...? X_X
There are two types of ring strain:
(1) torsional strain:
think about t-butyl groups on every carbon of a cyclohexane--very crowded right? that's torsional strain--all the hydrogens around each other. the hydrogens want to be furthest away from each other. that's why for cyclohexanes, the bulkiest groups are favored in the equatorial position..but this is going far more in depth than is needed)
(2) angle strain: http://research.cm.utexas.edu/nbauld/teach/cycloprop.html
That site talks about it in more detail.
I hope this was somewhat helpful...? X_X
Why are people posting serious answers in this thread? 

it weirds me out when people type things like the above
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