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A car moving at 35m/s on dry pavement, skids to a stop in 7 seconds. What is the coefficient of friction between the car's tires and the pavement?
a. .2
b. .5
c. 1
d. 2
a. .2
b. .5
c. 1
d. 2
I would start by finding time by using average velocity = Vfinal + Vinitial /2 = 35+0/2 = 17.5 m/s. And if D=175m then Time=10 seconds. A car moving at 35 m/s on dry pavement, skids to a stop over 175 m. What is the coefficient of friction between the car’s tires and the pavement?
Lol, Xishen... Gotta read the question man.i don't think the above calculation is correct, maybe i'm wrong.
first of all think logically, going back to the original question where the car skids to a stop in 7 seconds, after getting a = -5m/s*s, plug that into this equation: Vf=Vo + 2ad, where (Vf=0, Vo=35, a=-5m/s*s), you would get d = 3.5m. and with a coefficient of .5 it skids for that long to come to a stop.
the question states it comes to a stop this time in 175(!!!) meters, that immediately tells me the coefficient of friction is tiny, that's why it took so long (both in time and distance) to stop.
my calculation:
given: Vf = 0, Vo= 35, X=175, a=?
now use this formula to find a: Vf^2 = Vo^2 + 2ad => a = -.1m/s*s
since F friction = F net (they are both in the negative direction btw so no need for negating signs here)
Muk * N = ma
Muk * mg = m(0.1)
Muk = 0.1 / 10
Muk = 0.01
this makes sense to me because since the friction force is tiny (due to the property of the road surface or tire), it's almost like breaking on ice (very low friction), where it would take you a long distance before you come to a stop. and your answer 0.35 is still relatively close to .5 for Muk, which is disproportional to the dramatic difference in distance needed to come to a stop (3.5m vs 175m)
And,,, your kidding right? The equation is correct so I am not sure where the error occurred... but I'll help you with the arithmetic.my calculation:
given: Vf = 0, Vo= 35, X=175, a=?
now use this formula to find a: Vf^2 = Vo^2 + 2ad => a = -.1m/s*s
You dont need mass to solve this problem. 1/2mv^2=MuGD and the M cancelyup that works. think this was a prolem in EK.
if you had the mass of the car you could solve it as a work problem. W = change in energy = change in momentum