For BS, quesiton 105, can someone please explain why doubling the S chromosome products makes the imbalance worse (rather than better)?
Thanks!
The term is dosage compensation and humans use the same mechanism for controlling gene expression for sex-linked genes. In this problem, RS means you're female while RR means you're male. You are not concerned about the gene expression for S because, for example in human males (XY), the Y chromosome is mostly a sex determinant.
So the real question is: how do I make sure the total gene expression of genes on R is the same for both males and females. Any of these ways are possible and are actually observed in different species.
1) Reducing the transcription of each R chromosome for males to half.
2) Doubling the transcription of the R chromosome for females.
3) Inactivating one of the R chromosomes for males.
Human females undergo dosage compensation through X-inactivation.
was this ever figured out? i am at an utter loss
I didn't really read everybody's take on this question, but here's just reasoning.
Of all the choices,
(A) is the only one that can be correct.
(B) is not correct because peptides are synthesized from the N-terminus to the C-terminus. It would not make sense to have the carboxy-terminal stay the same, but have an altered amino-terminal sequence.
(C) is not correct because an addition of one nucleotide will not generate an additional amino acid in this case. The question states that the change does not create or eliminate a stop codon. I'm guessing the test writers meant that there will not be a new stop codon in a new location, though the actual codon may have changed sequence.
(D) is not correct with the same logic as
(C).
For
(A) to be correct, the insertion would need to:
Shift the sequence such that a new codon appears in the exact location as the old stop codon. (i.e. the stop codons need to be interwoven in each other from the initial transcript - the first two nucleotides of the old stop codon need to be the last two nucleotides of the new stop codon and the last codon translated needed to end with a U)
This cannot be happen. The condition simply cannot be met, so I have no idea why (A) can even be a plausible answer, but it is certainly a "better choice" over (B), (C), and (D).