Look at the reactant. Notice that the nitrogen has been fully alkylated. This is step 1 of Hoffman elimination. Normally you then react this molecule with silver oxide (or silver iodide i forget which one. Out right now. Check my notes for correct workup) and then dehydrate and heat it but it gies directly to step 3. Notice how the molecule reacts with oh- and heat. This signifies you are doing Hoffmann elimination and thus will generate the less substituted double bond.
If you download my notes and go to the last chapter (amines), I go over the Hoffman elimination. You should check it out