Q: Alkenes are more acidic than alkanes. What is the best explanation for this trend?
I thought it was because the sigma bond present in alkenes helps to stabilize the negative charge generated when a proton is removed.
Reason why I jumped the gun on sigma bond stabilization: s orbitals are closer to the nucleus than p orbitals are. So electrons that are in s orbitals will be closer to the nucleus than electrons in p orbitals and therefore, lower energy (opposite charges attract). For this reason, electrons that are in sp orbitals are lower energy than sp2, which is lower energy than sp3, since they have greater s character (33% for sp2) than sp3 (25%). This makes the anions more stable. That's why alkyne protons are more acidic than alkenes>alkanes...
But the correct answer is that the pi bond present in alkenes help to stabilize the negative charge generated when a proton is removed.
The answer key just says because alkanes and alkenes both have sigma bonds so that eliminates sigma bond stabilization
I understand a negative charge that is adjacent to one or more Pi bonds can disperse its negative charge over multiple atoms (aka resonance) So a negatively charged alkane is much less stable than a negatively charged alkene, where the negative charge can be dispersed over multiple carbons through resonance.
Can someone explain why my thought process was wrong? Does sigma bond (and therefore s character) not play as big a role to the acidity of alkenes as they do for alkynes? Is it because the difference between s character of alkenes and alkanes are not as great as the contribution of pi bonds to this stabilization to make alkenes more acidic?
I guess I thought s character was important because all the textbooks I had said alkynes s-character was the reason why it was more acidic and applied that same concept between alkenes and alkanes.
Any enlightment would be greatly appreciated.
I thought it was because the sigma bond present in alkenes helps to stabilize the negative charge generated when a proton is removed.
Reason why I jumped the gun on sigma bond stabilization: s orbitals are closer to the nucleus than p orbitals are. So electrons that are in s orbitals will be closer to the nucleus than electrons in p orbitals and therefore, lower energy (opposite charges attract). For this reason, electrons that are in sp orbitals are lower energy than sp2, which is lower energy than sp3, since they have greater s character (33% for sp2) than sp3 (25%). This makes the anions more stable. That's why alkyne protons are more acidic than alkenes>alkanes...
But the correct answer is that the pi bond present in alkenes help to stabilize the negative charge generated when a proton is removed.
The answer key just says because alkanes and alkenes both have sigma bonds so that eliminates sigma bond stabilization
I understand a negative charge that is adjacent to one or more Pi bonds can disperse its negative charge over multiple atoms (aka resonance) So a negatively charged alkane is much less stable than a negatively charged alkene, where the negative charge can be dispersed over multiple carbons through resonance.
Can someone explain why my thought process was wrong? Does sigma bond (and therefore s character) not play as big a role to the acidity of alkenes as they do for alkynes? Is it because the difference between s character of alkenes and alkanes are not as great as the contribution of pi bonds to this stabilization to make alkenes more acidic?
I guess I thought s character was important because all the textbooks I had said alkynes s-character was the reason why it was more acidic and applied that same concept between alkenes and alkanes.
Any enlightment would be greatly appreciated.