This is from Kaplan Blue Book, page 667 number 16

Q: A colorblind male XcY is crossed with a normal female who is a carrier of fragile X and colorblindness (XfXc). What is the probability that a male child will be phenotypically normal?

A: 0%

My questions

1. how can a normal female carry fragile x and colorblindness?

I say that woman is abnormal.

2. XfXc, XcXc, XfY and XcY are the 4 diff combinations.

How can i tell which is normal and which is not to find the answer is 0%?

Q: A colorblind male XcY is crossed with a normal female who is a carrier of fragile X and colorblindness (XfXc). What is the probability that a male child will be phenotypically normal?

A: 0%

My questions

1. how can a normal female carry fragile x and colorblindness?

I say that woman is abnormal.

2. XfXc, XcXc, XfY and XcY are the 4 diff combinations.

How can i tell which is normal and which is not to find the answer is 0%?

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