but if it was 14,15,15,17 it would be same....??Quantum numbers are n, l, m(sub.l), m(sub.s). Confusing, but heres the gist of it:
n represents your row number. Chlorine is in the 3rd row, so n=3. Easy.
"L" can be a range of numbers from 0 to one less than n (n=3, so L can range from 0 to 2). These numbers (0,1,2) represent the possible shells a valence chlorine electron can reside. 0=s 1=p, 2=d. Since we're dealing with the 13th electron, we're in a P orbital (so n=1)
"MsubL" represents the possible sub-shells the valence chlorine electron can reside. Numerically, MsubL=+ or -(L). Since we're looking at a P orbital, L=1. Thus, each sub-shell correlates to -1, 0, and 1. Then we fill the subshells with 1 electron each before doubling up (sounds familiar?). Since the 13th electron is the only electron in our P orbital, its gonna end up in the -1 sub-shell. So... MsubL=-1.
MsubS is easy. Its just the electron spin (what are thooseee). Who knows, and who cares. Just remember its either +1/2 or -1/2.
So, to summarize:
N = 3
L = 1
MsubL = -1
MsubS = +/- 1/2
Pretty sure you knew all this, but I'm just covering bases here. And heres my point:
Note how L and MsubL would have been completely different if we were asked to solve for the 11th or 12th electron.
Well, no.but if it was 14,15,15,17 it would be same....??
Yep, thats exactly it. If they ask for the 5th electron of chlorine, you just refer to the 5th element on the periodic table for your quantum numbers. The only exception is that your N value is representative of chlorine.no i know what the m l and all that stuff is i literally just write out the configuration and i can get everything from it.
but when they said 13th Electron of Cl i got confused.. i don't know if that means count to 13 then use that Elements configuration to get n l m or what thats what i got confused and i still don't think i get if i can or not
ok so was i right by going to Al when they asked for 13th electron of chlorine??Yep, thats exactly it. If they ask for the 5th electron of chlorine, you just refer to the 5th element on the periodic table for your quantum numbers. The only exception is that your N value is representative of chlorine.