chads molality ?

[molar3]

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What is the molality of an aqueous solution of a non-electrolyte that has a freezing point of -0.62°C (KF,water=1.86°C/m)?

Tf= - kfm= - (1.86 c/m) (4m)= -0.62
molal=.33



i got the molal being .33 but i did it a diff way, what my question is , where is getting that the molal is 4m above in the parenthesis? i thought we were solving for m so why does he have 4 there?...maybe im not reading this problem right, but can any1 clarify?

 

[herkulease]

I'm not sure where that 4 comes from.

typo perhaps. Since its a non-electrolyte it wouldn't ionize so "i" would be 1.

 

[HannibalLecter]

What is the molality of an aqueous solution of a non-electrolyte that has a freezing point of -0.62°C (KF,water=1.86°C/m)?

Tf= - kfm= - (1.86 c/m) (4m)= -0.62
molal=.33



i got the molal being .33 but i did it a diff way, what my question is , where is getting that the molal is 4m above in the parenthesis? i thought we were solving for m so why does he have 4 there?...maybe im not reading this problem right, but can any1 clarify?

Yup the 4m actually needs to be replaced with a variable we don't even know what the molality is

 

[molar3]

ok thanks guys, i guess it is a typo bc it doesnt make sense otherwise. i was starring at this prob getting so frustrated ! haha