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chem question

Discussion in 'DAT Discussions' started by BodybldgDoc, Mar 4, 2007.

  1. BodybldgDoc

    BodybldgDoc Guest

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    How many atoms of carbon are in 4.00*10^-8 grams of C3H8?
    A. 1.64*10^15
    B. 2.34*10^11
    C. 1.89*10^14
    D. 4.66*10^2
    E. 4.00*10^4

    This is how i solved it. Can someone please tell me if its right?

    4*10^-8 g of C3H8 * 1mol of C3H8/44g of C3H8 * 3mol of C/1mol of C3H8 * 6*10^23 atoms of C/1 mol of C =1.7*10^15
     
  2. dat_student

    dat_student Junior Member
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    :thumbup:
     
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  3. OP
    OP
    BodybldgDoc

    BodybldgDoc Guest

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  4. joonkimdds

    joonkimdds Senior Member
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    wrong~
    6.022x10^22 instead of 6x10^22 :love:
    and i believe this will give u the 1.64x10^15 so the A is the answer.
    By the way, is #atom same as #molecules?
    I know that there are 6.022x10^22 molecules in 1 mol but then that means
    there should be the same amount of atoms :confused::eek::scared:
     
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