Can anyone tell me where the number, 2.303, comes from? Q. Given that the E(standard) for Au+3/Au is 1.50V and the E for Li+/Li is -3.05V, what is Ecell? Sol. Ecell= Ecell(standard)-RT/nF logQ Ecell= Ecell(Standard)-(0.0591/n)logQ 0.0591 is a constant equal to 2.303RT/F at 298K I don't know how to get the 2.303.