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Can anyone tell me where the number, 2.303, comes from?
Q. Given that the E(standard) for Au+3/Au is 1.50V and the E for Li+/Li is -3.05V, what is Ecell?
Sol.
Ecell= Ecell(standard)-RT/nF logQ
Ecell= Ecell(Standard)-(0.0591/n)logQ
0.0591 is a constant equal to 2.303RT/F at 298K
I don't know how to get the 2.303.
Q. Given that the E(standard) for Au+3/Au is 1.50V and the E for Li+/Li is -3.05V, what is Ecell?
Sol.
Ecell= Ecell(standard)-RT/nF logQ
Ecell= Ecell(Standard)-(0.0591/n)logQ
0.0591 is a constant equal to 2.303RT/F at 298K
I don't know how to get the 2.303.