concentration calculation problem
Started by Smooth Operater
let me guess...
we get molar mass of NaCl and get the difference with 0.585g to find out how much is gone then using the ratio get the original volume other than 25ml. using those two new numbers we found substitute it into
concentration= molarity = g/volume at the start.
am i wrong? i think i m wrong 😀
the correct answer is 0.585g/58.5 g/mole * 0.025L . But I am not sure how you would get it lo?
Advertisement - Members don't see this ad
You have .585 g of salt in 25 ml of solution. For 1 liter you would have
25:.585=(1000):xg solving for x
x=40 (.585) g/L
1 molar would be 58.5g, then
1m:58.5=?M: (40)(.585)
solving for m= (40)(.585):58.5
M=.4
25:.585=(1000):xg solving for x
x=40 (.585) g/L
1 molar would be 58.5g, then
1m:58.5=?M: (40)(.585)
solving for m= (40)(.585):58.5
M=.4
mmm, ur answer is still wrong.
does 0.585 g = 0.585 ml?
does 0.585 g = 0.585 ml?
What is the correct answer?
for salt, 0.585g is not equal to 0.585ml
for salt, 0.585g is not equal to 0.585ml
what type of concentration are you being asked about? Molality, molarity, or molar-percentage, or weight-percentage?
molarity
It is a 0.4 Molar solution (moles/liter), and
25ml (0.025L) contains .585g/58.50g/moles. The answer is in moles present in 25 ml not the molarity of the solution.
25ml (0.025L) contains .585g/58.50g/moles. The answer is in moles present in 25 ml not the molarity of the solution.
