dice probability quesitons

[joonkimdds]

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1) A six sided die is thrown twice. What is the probability that the sum or the product of the two numbers thrown will be odd ?

2) A six sided die is thrown twice. What is the probability that the sum or the product of the two numbers thrown will be even ?

 

[joonkimdds]

i got it.

 

[yakuza]

I couldn't figure it out. How did you do it?

 

[joonkimdds]

I couldn't figure it out. How did you do it?

I used Sharingan to do it 😀

 

[yakuza]

I used Sharingan to do it 😀

lol, I would also but I just used mine for my crack dat test. So I'll just hurt myself if I use it again..

 

[joonkimdds]

lol, I would also but I just used mine for my crack dat test. So I'll just hurt myself if I use it again..

yeah, crack dat is like the 8 tailed beast who owned Sasuke yesterday 😀

For this problem, what i did was listing all the possibilities and multiplying, adding them all. I used a long way to do it, so if i list all the possibilities, u will be like 😱 and and 🙁 and 👎 cuz i used dumb method. I think it's better to ask someone who knows a short cut.

 

[DrDentista]

1) A six sided die is thrown twice. What is the probability that the sum or the product of the two numbers thrown will be odd ?

To get Odd sum or product: 1+2, 2+3, 3+4, 4+5, 5+6, 1X3, 1X5, 3X5,

n = 8
r = 2

(8!/ ( 2! (6!)!) (1/6) ^ 2 (5/6) ^ 6



do the second one like that...well that's what I would do, ...🙂

 

[Streetwolf]

1) A six sided die is thrown twice. What is the probability that the sum or the product of the two numbers thrown will be odd ?

2) A six sided die is thrown twice. What is the probability that the sum or the product of the two numbers thrown will be even ?

1. Odd sum needs 1 odd number and 1 even number. Odd product needs two odd numbers. What's left? Two evens. Probability of two evens is 1/2 * 1/2 = 1/4. So 1 - 1/4 = 3/4 which is the answer.

2. Even sum needs 2 evens or 2 odds. Even product needs two evens or 1 odd and 1 even. That covers everything. Probability is 1.