probability of playing cards

[caffeine jitters]

Hello everyone

I am wondering if an equally acceptable way to solve this type of problem is to just cut the permutation in half because we have two unique variables. The way it was explained seemed a little too overboard for me.
Please let me know if there are cases when this wouldn't work?

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Thanks guys

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[MickeyMug]

This is usually a quicker way so I would definitely practice this one since time on the QR section is your enemy.
If you have a subscription with CourseSave.com I would recommend watching Chad's videos on permutation and probability too they're pretty helpful IMO.