# EK 1001 chemistry problem 282

Status
Not open for further replies.

#### umdnjmed

##### Full Member
10+ Year Member
5+ Year Member
Suppose the reaction:
CO(g) + Cl2(g) ---> COCl2 (g)
has an equalibrium constant of 530. What is the equalibrium constant of the reaction.
2CO(g) + 2Cl2(g) ---> 2COCl2 (g)

EK solution says that since everything doubled, means everything was squared in equalibrium expression therefore Keq is squared as well.

I understand the mathematics behind the answer but doesn't this answer suggest that the concentration of reactants and products affects the equilibrium constant? if i recall correctly, keq is independent of [R] and [P], or does this apply only to reactions which are already at equilibrium?

#### ssdfrb

##### Full Member
10+ Year Member
i just did this problem and i dont get their explanation either...

if you substitute numbers into the equilibrium constant you should get the same number for both reactions.

#### mehc012

##### Big Damn Hero
7+ Year Member
i just did this problem and i dont get their explanation either...

if you substitute numbers into the equilibrium constant you should get the same number for both reactions.

No, you'll still get the square of the original. Squares don't cancel like a constant; (xy)^2/z^2 does not equal xy/z. If you plug in numbers, you'll see the same thing:

(2*3/4) =/= (4*9/16)

You're multiplying the top and the bottom by different numbers, so you will get a different fraction.

#### ssdfrb

##### Full Member
10+ Year Member
wow. just redid the math.

7+ Year Member

#### SN2ed

##### Full Member
Moderator Emeritus
10+ Year Member
7+ Year Member
Thread closed. These types of questions belong in the MCAT Study Q&A forum.

Status
Not open for further replies.