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I'm just trying to make sure I have this correct:
When balancing a redox reaction, you need to make sure the molar ratio of electrons is equal for both half reactions. For example, if the reduction half rxn equation has 2e and the oxidation half rxn equation has simply e, you need to multiply the oxidation half rxn equation by 2 in order to balance the two half rxns.
However, for calculating the electric potential of a electrochemical cell its simply the reduction plus the oxidation potential (they are almost always written as the reduction potential, so it would be the largest + reduction potential added to the opposite of smallest reduction potential, so the Ecell is ultimately positive). This does not involve any balancing like in the redox rxns....correct?
When balancing a redox reaction, you need to make sure the molar ratio of electrons is equal for both half reactions. For example, if the reduction half rxn equation has 2e and the oxidation half rxn equation has simply e, you need to multiply the oxidation half rxn equation by 2 in order to balance the two half rxns.
However, for calculating the electric potential of a electrochemical cell its simply the reduction plus the oxidation potential (they are almost always written as the reduction potential, so it would be the largest + reduction potential added to the opposite of smallest reduction potential, so the Ecell is ultimately positive). This does not involve any balancing like in the redox rxns....correct?
