- Joined
- Jul 15, 2015
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Competitive inhibitors don't change Vmax, while uncompetitive/noncompetitive inhibitors do.
Why? They all do the same basic thing - prevent substrate from being processed by the enzyme. But the way they do it is different. However, for the purposes of my question, please address the following:
- Why does adding substrate to a rxn help overcome the effects of competitive inhibitors? Once the inhibitor binds, doesn't it remain bound to the active site? If not, why does it detach? What's the point of being an inhibitor if it doesn't permanently inhibit the active site?
- Is the reason for competitive inhibitors detaching from an enzyme due to increased substrate concentration answered by looking at binding affinity?
For example: there are a million enzymes and some substrate particles in a rxn mixture. I then add competitive inhibitors, which bind to some of the enzymes. Will these enzymes be permanently bound by the inhibitors, such that they will no longer be functional for the remainder of the rxn?
Why? They all do the same basic thing - prevent substrate from being processed by the enzyme. But the way they do it is different. However, for the purposes of my question, please address the following:
- Why does adding substrate to a rxn help overcome the effects of competitive inhibitors? Once the inhibitor binds, doesn't it remain bound to the active site? If not, why does it detach? What's the point of being an inhibitor if it doesn't permanently inhibit the active site?
- Is the reason for competitive inhibitors detaching from an enzyme due to increased substrate concentration answered by looking at binding affinity?
For example: there are a million enzymes and some substrate particles in a rxn mixture. I then add competitive inhibitors, which bind to some of the enzymes. Will these enzymes be permanently bound by the inhibitors, such that they will no longer be functional for the remainder of the rxn?