Fraction problem

[joonkimdds]

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Q. Put the following in increasing order:

I. (square root of 2)/3
II. (Square root of 3)/4
III. (Square root of 5)/5

what I did was making them have the common denominator of 60, and they were

I. [20(Square root of 2)]/60
II. [15(Square root of 3)]/60
III. [12(Square root of 5)]/60

I think the biggest number is I, and the lowest Number is III.
So i thought that the answer should be III<II<I

but the answer is II< III< I

how is III bigger than II?

 

[sgdorfl90]

I think the easiest way to do this is to square them all..one is no doubt the biggest, so now its between 2 and 3. squaring 2 gives up 3/16, and squaring 4 gives up 5/25=1/5=.2.....clearly 3/16 is smaller then .2, so the answer looks correct.

 

[joonkimdds]

OH! i got it~ nvm