G Chem Question

[SuperCool101]

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During a titration it was determined that
30.00 mL of a 0.100 M Ce4+ solution was
required to react completely with 20.00
mL of a 0.150 M Fe2+ solution. Which
one of the following reactions occurred?​

A. Ce4+ + 3Fe2+ + H2O ---------> 3Fe3+ + CeO- + 2H+​

B. 2Ce4+ + Fe2+ ----------> Fe4+ + 2Ce3+​

C. Ce4+ + Fe2+ -----------> Fe3+ + Ce3+​

D. Ce4+ + 2Fe2+ -----------> 2Fe3+ + Ce2+​

E. Ce4+ + 2Fe2+ ------------> 2Fe4+ + Ce2+ + 2e-​

The correct answer is C.
My question is, why can't the answer be D??

 

[Baylor2011]

You're reacting equal moles of reactant..To find this out, figure out how many moles are reacting!

0.100 mol Ce4+/1L X 0.03L = 0.003mol Ce4+
0.150 mol Fe2+/1L X 0.02L = 0.003mol Fe2+

Equal moles of reactants means all coefficients need to be 1.

 

[SuperCool101]

You're reacting equal moles of reactant..To find this out, figure out how many moles are reacting!

0.100 mol Ce4+/1L X 0.03L = 0.003mol Ce4+
0.150 mol Fe2+/1L X 0.02L = 0.003mol Fe2+

Equal moles of reactants means all coefficients need to be 1.

yes, i was thinking about that too, now it makes more sense.

Thank you

 

[Baylor2011]

You're welcome