G-chem Quetions

[howui3]

need some help with these:

Q1:

given that Zn + CuSO4 -> ZnSO4 + Cu with E=+1.1v
if 48,250 C of charge are produced in 10min, how many grams of CU are deposited? (1Faraday=96,000C/mol) and Cu=64g/mol


Q2:

the solubility of CaF2 (Ksp=4x10-11) in 0.1M solution of Ca(NO3)2 is..?


thanks!

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[Rook]

need some help with these:

Q1:

given that Zn + CuSO4 -> ZnSO4 + Cu with E=+1.1v
if 48,250 C of charge are produced in 10min, how many grams of CU are deposited? (1Faraday=96,000C/mol) and Cu=64g/mol


Q2:

the solubility of CaF2 (Ksp=4x10-11) in 0.1M solution of Ca(NO3)2 is..?


thanks!

Hey Gil,

If the answers are 16 g of Cu and Solubility 4x10^(-9)
Then I can teach you. do you know the answers?

 

[mahGOL]

if the answer to Q1 is 32.166g and Q2 10^ -5 I will explain it to you.

need some help with these:

Q1:

given that Zn + CuSO4 -> ZnSO4 + Cu with E=+1.1v
if 48,250 C of charge are produced in 10min, how many grams of CU are deposited? (1Faraday=96,000C/mol) and Cu=64g/mol


Q2:

the solubility of CaF2 (Ksp=4x10-11) in 0.1M solution of Ca(NO3)2 is..?


thanks!

 

[dat_student]

...
Q1:

given that Zn + CuSO4 -> ZnSO4 + Cu with E=+1.1v
if 48,250 C of charge are produced in 10min, how many grams of CU are deposited? (1Faraday=96,000C/mol) and Cu=64g/mol
...

Zn ------------> Zn2+ + 2 e
Cu2+ + 2 e ----> Cu

48,250 C
____________ = 0.5 moles of electrons
96,000 C/mole

We see that the exchange of 2 moles of electrons would give 1 mole of Cu:

0.5 moles e * (1 mole cu / 2 moles e) * ( 64 g / mole ) = 16 g CU (deposited)


NOTE: Faraday is the magnitude of the charge on 1 mole of electrons:
(1.6 * 10^-19 C /e)(6.02 * 10^23 e/mole) = approx 96,500 C/mole

 

[dat_student]

...

Q2:

the solubility of CaF2 (Ksp=4x10-11) in 0.1M solution of Ca(NO3)2 is..?

...

CaF2 <--> Ca2+ + 2F-
...............0.1 M + 2S

(0.1 M)(2S)^2 = 4 * 10 ^ -11

0.4 S^2 = 4 * 10^-11

S^2 = 10^-10

S = 10^-5

 

[howui3]

CaF2 <--> Ca2+ + 2F-
...............0.1 M + 2S

(0.1 M)(2S)^2 = 4 * 10 ^ -11

0.4 S^2 = 4 * 10^-11

S^2 = 10^-10

S = 10^-5

money!!!

it's been a while...

 

[howui3]

Hey Gil,

If the answers are 16 g of Cu and Solubility 4x10^(-9)
Then I can teach you. do you know the answers?

the first one is 16grams.

the second one is 1x10-5, dat_student has the correct calculations