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Circle g.s. [ground state]; e.s. [excited state]; or i [incorrect]
Which one of these in the excited state and why?
Which one of these in the excited state and why?
eissa said:Circle g.s. [ground state]; e.s. [excited state]; or i [incorrect]
Which one of these in the excited state and why?
issa said:Circle g.s. [ground state]; e.s. [excited state]; or i [incorrect]
Which one of these in the excited state and why?
tom_servo_dds said:e) e - not the correct filling order
whiskeysour said:wrong, it is the correct filling order.
whiskeysour said:wrong, it is the correct filling order.
JohnDoeDDS said:C is correct abd still have the ground state. E is the excited state
issa said:P has a 5 not 6 in part e. is e in the excited state or not? and anyone have the correct explanation?
yesSiubking said:You got an A in general chemistry?
joonkimdds said:I think only B and D are correct. All the others have at least 1 or 2 problems.
B has n=2, D has n=3. Excited state is anything beside n=1 or ground state so I think both B and D should be the answers.
Therefore, there is no ground state, B and D are excited state, and all the others are incorrect. I bet I am 100 % correct
creestoL said:Can you please explain why e is incorrect? also, n=2, n=3...that refers to the electron shell right? how did you determine it was 2 and 3? thanx. also, if the OP can post the answers, that would be helpful.
aranjuez said:issa, e cannot occur as there is no such thing as 2d. There are only 2s and 2p. Remember the order of filling: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, etc.
s gets 2, p gets 6, d gets 10, and so on.
e is not an excited state. It's an impossible "state" per the rules.
aranjuez
aranjuez said:issa, e cannot occur as there is no such thing as 2d. There are only 2s and 2p. Remember the order of filling: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, etc.
s gets 2, p gets 6, d gets 10, and so on.
e is not an excited state. It's an impossible "state" per the rules.
aranjuez
joonkimdds said:Yay~ so i was correct!
Community College Rules!
Woo HOo~~!
aranjuez said:Wupps! Sorry about that. You're right. It was for f.
aranjuez
joonkimdds said:E is incorrect because of 2d
here is the order it is supposed to be
1s2
2s2
2p6
3s2
3p6
4s2
3d( )
4p6
2d doesn't exist.
Kaplan blue book says it doesn't matter if u state 4p before 3d or vice versa.
but anyway, 2d doesn't exist. d starts from 3d.
and if you want more explanation, u should be clear about what's the answer and what's not. because even if i say this, there is no guarantee i am 100% right and i can make things worse if i keep insisting that my wrong answer is correct, if u know what i am saying...
plz tell me what the answer is.
issa said:Circle g.s. [ground state]; e.s. [excited state]; or i [incorrect]
Which one of these in the excited state and why?
joonkimdds said:same here~ lol but it's becuz u linked the photo so whenever i click it the entire window goes to that link and i have to press back and so on.
if i quote the problem, there wasn't this mistake
anyway, I still believe that anything beside n=1 is excited state becuz n=1 is called ground state.
at least that's what i read from the book.
dat_student said:e is the correct answer without a doubt
Ground state:
1s2 2s2 2p6 3s1
Excited state:
1s2 2s2 2p5 3s2
(one of the electrons in one of the p suborbitals is excited and moved to the next shell (i.e. shell #3, orbital S))
Envision said:i agree. DAT student, what about b and d? i was under the impression that they are in gs. what do you think?
Envision said:i agree. DAT student, what about b and d? i was under the impression that they are in gs. what do you think?