H-nmr

Started by Kami
This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

Kami

Member
15+ Year Member
20+ Year Member
Advertisement - Members don't see this ad
In 1H-NMR spectrum, how many peaks will there be in m-xylene (1,3-dimethyl benzene? Can anyone explain?
 
Someone can correct me if I'm wrong... and I won't try to figure out shielding.

Four separate peaks.

Peak 1: H on carbon 2. Will be a singlet.
Peak 2: H on the methyl groups. Will be a singlet.
Peak 3: H on carbons 4 and 6. Will be a doublet.
Peak 4: H on carbon 5. Will be a triplet.
 
Someone can correct me if I'm wrong... and I won't try to figure out shielding.

Four separate peaks.

Peak 1: H on carbon 2. Will be a singlet.
Peak 2: H on the methyl groups. Will be a singlet.
Peak 3: H on carbons 4 and 6. Will be a doublet.
Peak 4: H on carbon 5. Will be a triplet.

It is correct, but would they ask you how far upfied they are located. If they do, then the most upfield signal should be Peak 1 and the most downfield signal should be peak 2.

Correct me if i am wrong!
 
my guess and from my experience there was not any NMR, mass spec or IR on the DAT so dont worry