- Joined
- Jan 26, 2007
- Messages
- 162
- Reaction score
- 1
Which one was really hardest Science Class for you?
For me it's Gen Chem 2..........................What about you?
For me it's Gen Chem 2..........................What about you?
Mathematical logic
The following sentence is true. The preceding sentence is false.
lol and proving that 1+1=2 is not a simple task.
hmmm....
definitely partial differential equations or advanced mechanics.
Bio-freaking-chem 2! It's all memorization of pathways and structures, and it seems like all my study-mates can look at a page and then draw it 15 minutes later, while it takes me two hours of repeatedly drawing it. I was killing so many trees I switched to a mini dry erase board. Then by the time I learn three more pathways, I've forgotten the first one.
And now, all the people below me on the curve have dropped.
Sucks to get my butt handed to me by a memorization course. Sorry for the rant.
Any tips?
Mathematical logic
The following sentence is true. The preceding sentence is false.
lol and proving that 1+1=2 is not a simple task.
Spelling?
haha.
you can prove it by counter example.
The proof starts from the Peano Postulates, which define the natural
numbers N. N is the smallest set satisfying these postulates:
P1. 1 is in N.
P2. If x is in N, then its "successor" x' is in N.
P3. There is no x such that x' = 1.
P4. If x isn't 1, then there is a y in N such that y' = x.
P5. If S is a subset of N, 1 is in S, and the implication
(x in S => x' in S) holds, then S = N.
Then you have to define addition recursively:
Def: Let a and b be in N. If b = 1, then define a + b = a'
(using P1 and P2). If b isn't 1, then let c' = b, with c in N
(using P4), and define a + b = (a + c)'.
Then you have to define 2:
Def: 2 = 1'
2 is in N by P1, P2, and the definition of 2.
Theorem: 1 + 1 = 2
Proof: Use the first part of the definition of + with a = b = 1.
Then 1 + 1 = 1' = 2 Q.E.D.
Note: There is an alternate formulation of the Peano Postulates which
replaces 1 with 0 in P1, P3, P4, and P5. Then you have to change the
definition of addition to this:
Def: Let a and b be in N. If b = 0, then define a + b = a.
If b isn't 0, then let c' = b, with c in N, and define
a + b = (a + c)'.
You also have to define 1 = 0', and 2 = 1'. Then the proof of the
Theorem above is a little different:
Proof: Use the second part of the definition of + first:
1 + 1 = (1 + 0)'
Now use the first part of the definition of + on the sum in
parentheses: 1 + 1 = (1)' = 1' = 2 Q.E.D.
multivariable calculus...the third dimension was too much for me.
Orgo, lowest grades on my tranny
Mathematical logic
The following sentence is true. The preceding sentence is false.
lol and proving that 1+1=2 is not a simple task.