Help With a Data Math Question

[wswgoalie1]

Hey guys, so I was tutoring a student, but got stuck on this question:

A cooler has 24 Greek Yogurt containers and 6 vanilla yogurt containers. The person in charge of the yogurt reaches into the cooler (without looking) and randomly picks them out of the cooler. What is the probability that your friend gets a Greek yogurt and you get a vanilla yogurt? Leave answers as percentages rounded to one decimal place.

Also,

Another quesiton,
Two 4 sided dice are tossed and the sum of the down sides noted. A 4-sided die doesn't have an "up" face like a 6-sided die has, so the down side is used.
A. Create a probability distribution and graph for this experiment
B. Determine the expected value of the sum.

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[deleted480308]

Hey guys, so I was tutoring a student, but got stuck on this question:

A cooler has 24 Greek Yogurt containers and 6 vanilla yogurt containers. The person in charge of the yogurt reaches into the cooler (without looking) and randomly picks them out of the cooler. What is the probability that your friend gets a Greek yogurt and you get a vanilla yogurt? Leave answers as percentages rounded to one decimal place.

Also,

Another quesiton,
Two 4 sided dice are tossed and the sum of the down sides noted. A 4-sided die doesn't have an "up" face like a 6-sided die has, so the down side is used.
A. Create a probability distribution and graph for this experiment
B. Determine the expected value of the sum.

(24/30)x(6/29)=

 

[longhaul3]

In the second question you have to consider all the possible outcomes of a single roll of the dice (there are 16) and then just count how many give each possible sum. Then you can make a bar graph that will look smaller at the low and high numbers and larger in the middle, because there are more ways to sum to the numbers in the middle.

The expected value is a probability-weighted average of the sums. Multiply each possible sum by the probability of achieving that sum and add them all together.

Also, depending on how specifically you read the first question, the above answer may be off by a factor of 1/2. There are two possible scenarios in which a Greek and vanilla yogurt are chosen: in one, you get the Greek (wrong outcome, depending on how much of a stickler you are for the question) and in the other, your friend gets the Greek (as written). Therefore, even given that the right yogurts are chosen, there is only a 1/2 probability that they end up in the right hands.