increasing galvanic cell voltage

Discussion in 'MCAT Study Question Q&A' started by happygirl, May 27, 2008.

  1. happygirl

    happygirl Member

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    So, my question is regarding how reactant concentration affects voltage of a galvanic cell. If the concentration is decreased significantly for instance, does voltage increase because, according to the Nernst equation, Q (reactant/products) is reduced and log of a fraction is a negative number so the right side of the equation becomes positive since a negative x a negative = a positive (sorry that was a confusing sentence)?

    Nernst Equation: E=Estandard -(2.30RT/nF)log[reactant]/[product]

    Ooooor, does increasing the reactant concentration increase voltage because the reaction moves more quickly to the right, meaning more electrons released at the anode and more electrons deposited on the cathode = higher voltage since since emf depends on number of electrons and rate of redox reaction? Or does this not apply because the cell is not at equilibrium? Am I confusing concepts?

    Thanks for the help!
     
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  3. fileserver

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    Q is always product/reactant. So you should be OK.
     
  4. happygirl

    happygirl Member

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    oh yeah! stupid mistake! :laugh:
     

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