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Taken from Chad's vids:
Which of the following changes to the following reaction at equilibrium would result in a shift to the right?
COCl2(g) + HCl(g)
CHCl3(l) + ½O2(g)
none of these
a decrease in pressure
removal of COCl2
an increase in the volume of the reaction vessel
It says the answer is none of these. And in the explanation it says that in general, removing a reactant and adding a product shifts the rxn left.
But I was looking at the number of moles of gas on each side, (since liquids usually don't affect le chatlier's principle). If you remove CoCl2 wouldn't it still move to the right because you would still have less moles on that side (1/2 mole o2) ? Please help me to understand this one!
Which of the following changes to the following reaction at equilibrium would result in a shift to the right?
COCl2(g) + HCl(g)
none of these
a decrease in pressure
removal of COCl2
an increase in the volume of the reaction vessel
It says the answer is none of these. And in the explanation it says that in general, removing a reactant and adding a product shifts the rxn left.
But I was looking at the number of moles of gas on each side, (since liquids usually don't affect le chatlier's principle). If you remove CoCl2 wouldn't it still move to the right because you would still have less moles on that side (1/2 mole o2) ? Please help me to understand this one!