Need help with hybridization question URGENT!!!

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sam26880

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what's the hybridization of each carbon in the figure below? And why are the 2 of the hydrogens flat and the other 2 are not?
 

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what's the hybridization of each carbon in the figure below? And why are the 2 of the hydrogens flat and the other 2 are not?

I think they should be all be flat...with 120* bond angles they should be trigonal planar and the whole molecule in one plane. Unless this is some exception that they show later on in Orgo.
 
I think they should be all be flat...with 120* bond angles they should be trigonal planar and the whole molecule in one plane. Unless this is some exception that they show later on in Orgo.



the two carbons on the sides are trigonal planar with 120 deg. angles. The carbon in the middle is Linear with 180 deg angle.
 
I think every thing should be in one plane because there is no tetrahedral structures...Id like to know why also if they are not in the same plane.
 
The reason why hybridization of the H2C=C=CH2 is not flat is due to where the pi bonds bond. One of the double bonds runs parallel to the paper while the other runs into and out of the paper. Let's imagine the XYZ grid. The X line will hook up to s bonds to each carbon. The reason is because once the pi bond is created on the lone carbon in the y axis, the extra pi bond location can run in the only in the z axis which twist the other CH2 90 degrees. If my explanation wasn't suffice, hopefully my picture will help
 

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