Let's say you have propane...CH3CH2CH3. Because of symmetry, the two methyl groups are equivalent. To figure out splitting, focus on a carbon and follow the n+1 rule, where n is the number of neighboring hydrogens. For example, carbon 1 of methane is is adjacent to a carbon with 2 protons. That group will show a triplet (2+1=3 peaks). Carbon 2 is influenced by 6 protons (3 from each of the neighboring carbons) so it will produce a spetet (again n=6 so 6+1=7). The final methyl group will also produce a triplet (for the same reason as carbon 1) but since both the methyl groups are equivalent, they will simply overlap with each other. For this reason, your NMR should have a septet and a triplet.
This is a simple case...I recommend you do some practice problems from your text. Hope that helps!